Question: indefinite blocking or starvation is problem related to ___
Answer:
indefinite blocking or starvation is a situation in which processes wait indefinitely within the semaphore. Indefinite blocking may occur if we remove processes from the list associated with a semaphore in LIFO (last-in, first-out) order.
MCQ: indefinite blocking or starvation is problem related to ___
Explanation:
indefinite blocking or starvation is a situation in which processes wait indefinitely within the semaphore. Indefinite blocking may occur if we remove processes from the list associated with a semaphore in LIFO (last-in, first-out) order.
Discuss a Question
Related Questions
- 1. In Priority Inversion Which of following Stands TRUE:
- 2. The bounded buffer problem is also known as :
- 3. In bounded buffer problem Which of the following Assumption Stands TRUE: <ol> <li>I. We assume that the pool consists of n buffers, each capable of holding one item.</li> <li>II. The mutex semaphore provides mutual exclusion for accesses to the buffer pool and is initialized to the value 1.</li> <li>III. The mutex semaphore provides mutual exclusion for accesses to the buffer pool and is initialized to the value 0.</li> <li>IV. The empty and full semaphores count the number of empty and full buffers.The semaphore empty is initialized to the value n; the semaphore full is initialized to the value 0.</li> <li>V. The empty and full semaphores count the number of empty and full buffers.The semaphore empty is initialized to the value 0; the semaphore full is initialized to the value n.</li> </ol>
- 4. The readers–writers problem and its solutions have been generalized to provide reader–writer locks on some systems. When a process wishes only to read shared data, it requests the reader–writer lock in____
- 5. The readers–writers problem and its solutions have been generalized to provide reader–writer locks on some systems. A process wishing to modify the shared data must request the lock in____
- 6. Multiple processes are permitted to concurrently acquire a reader–writer lock in read mode, but only one process may acquire the lock for ___, as exclusive access is required for ____
- 7. The Dining-Philosophers Problem Solution is:
- 8. All processes share a semaphore variable mutex, which is initialized to 1. Each process must execute wait(mutex) before entering the critical section and signal(mutex) afterward. Suppose that a process interchanges the order in which the wait() and signal() operations on the semaphore mutex are executed, resulting in the following execution: signal(mutex);...critical section...wait(mutex); In this situation
- 9. All processes share a semaphore variable mutex, which is initialized to 1. Each process must execute wait(mutex) before entering the critical section and signal(mutex) afterward. Suppose that a process replaces signal(mutex) with wait(mutex). That is, it executes wait(mutex);...critical section...wait(mutex); In this Case
- 10. in the following execution: signal(mutex);...critical section...wait(mutex); Suppose that a process omits the wait(mutex), or the signal(mutex), or both. In this case:
You may be interested in:
OS Process Synchronization MCQsRecently Added Articles
How Can AI Simplify the Academic Life of Students?
Last updated on: April 16, 2025Posted by: ExamRadar
Want to Clear IBPS RRB PO? Master These Mock Test Hacks!
Last updated on: March 10, 2025Posted by: ExamRadar
Top AI Tools for Instantly Detecting Plagiarized Writing
Last updated on: December 5, 2024Posted by: ExamRadar
Applying Algorithmic Trading Techniques to Forex: Insights for Programmers and Data Scientists
Last updated on: November 22, 2024Posted by: ExamRadar
Image to Text Conversion Made Easy: Online Tool Insights
Last updated on: April 12, 2024Posted by: ExamRadar
