Question: In a second order system, the steady state error is 0.02. if both viscous friction constant and spring constant are doubled, the steady error will be :
Answer:
MCQ: In a second order system, the steady state error is 0.02. if both viscous friction constant and spring constant are doubled, the steady error will be :
Correct Answer:
A. 0.01
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Related Questions
- 1. In second order system, the frequency of damped oscillations is 18 rad/s. The value of damping factor is 0.866. The natural frequency of oscillations is :
- 2. In a second order system, the peak overshoot is 100%. The value of damping factor is :
- 3. For a second order system, the settling time for ±2% band is _____________Where ξ = damping factor and ω<sub>η</sub> = natural frequency : rad/s.
- 4. In a second order damped system, the value of peak overshoot in per unit terms is :
- 5. A first order thermometer has a time constant of 50 s. it is subjected to a sinusoidal input cycling at 0.002 Hz. The time lag of instrument is :
- 6. In order that first order instrument should indicate an output which is within ±10% of the true value of the output when suspended to a sinusoidal input the product 𝛚Ϯ, where 𝛚 = angular frequency of input and Ϯ time constant of instrument should be :
- 7. A second order system when subjected to a unit step input has a peak overshoot of 10%. The same system when subjected to a sinusoidal input of unit amplitude will have a resonant peak of nearly :
- 8. A second order underdamped system has a damping factor of 0.8. it is subjected to a sinusoidal input of unit amplitude.it has resonant peak of :
- 9. Bandwidth, a frequency domain concept, is indicative of
- 10. An undamped second order instrument has a natural frequency of 500 Hz.it is subjected to a sinusoidal input of unit amplitude at 500 Hz. The amplitude of output is :
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