Question: A dc potentiometer is designed to measure up to about 2 volts with a slide wire of 800 mm. A standard cell of emf 1.18 volt obtains balance at 600 mm. a test cell is seen to obtained balance at 680 mm. The emf of the test cell is
Answer:
MCQ: A dc potentiometer is designed to measure up to about 2 volts with a slide wire of 800 mm. A standard cell of emf 1.18 volt obtains balance at 600 mm. a test cell is seen to obtained balance at 680 mm. The emf of the test cell is
Correct Answer:
A. 1.50 volts
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Related Questions
- 1. For measuring an ac voltage by an ac potentiometer, it is desirable that the supply for the potentiometer is taken from
- 2. The calibration of a voltmeter can be carried out by using
- 3. A slide wire potentiometer has 10 wires of 1 m each. With the help of a standard voltage source of 1.018 volt it is standardise by keeping the jockey at 101.8 cm. If the resistance of the potentiometer wire is 1000 Ω then the value of the working current is
- 4. The potentiometer is standardised for making it
- 5. Consider the following statements.A dc potentiometer is the best means available for the measurement of dc voltage because <ol> <li>The precision in measurement is independent of the type of detector used</li> <li>It is based on null balance technique</li> <li>It is possible to standardize before a measurement is undertaken</li> <li>It is possible to measure dc voltages ranging in value from mV to hundreds of volts Of these statements,</li> </ol>
- 6. In a dc potentiometer measurements, a second reading is often taken after reversing the polarities of dc supply and the unknown voltage, and the average of the two readings is taken. This is with a view to eliminate the effects of
- 7. Please check figures here to answer the Questions from 1-3. <img class="aligncenter size-full wp-image-13089" style="width: 200px; height: 150px;" src="http://examradar.com/wp-content/uploads/2021/04/fig-AC-Birdges-1.png" alt="" />in order that the bridge shown in fig be balanced
- 8. For the bridge shown in figure above Z<sub>1 </sub>= 200Ω ∠30°, Z<sub>2 </sub>= 150Ω ∠0°, Z<sub>3 </sub>= 250Ω ∠-40°. In order that the bridge can be balanced Z<sub>4 </sub>should be :
- 9. For the bridge shown in figure above , arm ab consists of resistance in series with an inductance, arms bc and ad consists of pure resistance. in order to achieve balance arm cd should consist of
- 10. The equations under balance conditions for a bridge are :R<sub>1</sub> = R<sub>2</sub> R<sub>3</sub> / R<sub>4 </sub>and L<sub>1 </sub>= R<sub>2</sub>R<sub>3</sub>C<sub>4</sub>Where R1<sub> </sub> and L1 are respectively unknown resistance and inductance.In order to achieve converging balance
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