Question: Sequential search has a time complexity of O(n), and binary search has a time complexity of O(log(n)). What difference will it make when the size n is 1000?
Answer:
MCQ: Sequential search has a time complexity of O(n), and binary search has a time complexity of O(log(n)). What difference will it make when the size n is 1000?
Correct Answer:
A. You would not notice much difference because computers run very fast
anyway
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Related Questions
- 1. Readthe following statements carefully, and choose the correct answer. I. The Ω notation is Anti Symmetric. II. The big Oh notation is Semi Equivalence.
- 2. Find the odd one out.
- 3. How many minimum number of spanning trees, one can have from a given connected graph with N nodes is having different weights for the edges.
- 4. The mathematical definition for Omega can be defined as, provided f,g:NR+ and c is a positive constant and n > n0,
- 5. The OBST algorithm in worst case takes _______ time if all c(i, j )’s and r(i, j)’s are calculated.
- 6. The notation is __________ I. Symmetric. II. Reflexive. III. Transitive.
- 7. Breadth first search uses __________ as an auxiliary structure to hold nodes for future processing.
- 8. From the following pick the one which does not belongs to the same paradigm to which others belongs to.
- 9. Primsalgorithm is based on _____________ method
- 10. The amount of memory needs to run to completion is known as_____________
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