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Question: In a <em>p</em>-type semiconductor, the conductivity due to holes (<em>σ<sub>p</sub></em>) is equal to (<em>e</em> is the charge of hole, <em>µ<sub>p</sub></em> is the hole mobility, <em>p</em>0 is the hole concentration):<em>1.p</em>0.<em>e</em>/<em>µ<sub>p</sub></em><em>2.µ<sub>p</sub>/p</em>0.<em>e</em>3.<em>p</em>0.<em>e</em>.<em>µ<sub>p</sub></em>4.None of the above.

Answer:

µp/p0.e
p0.e.µp

MCQ: In a <em>p</em>-type semiconductor, the conductivity due to holes (<em>σ<sub>p</sub></em>) is equal to (<em>e</em> is the charge of hole, <em>µ<sub>p</sub></em> is the hole mobility, <em>p</em>0 is the hole concentration):<em>1.p</em>0.<em>e</em>/<em>µ<sub>p</sub></em><em>2.µ<sub>p</sub>/p</em>0.<em>e</em>3.<em>p</em>0.<em>e</em>.<em>µ<sub>p</sub></em>4.None of the above.

Correct Answer: A. 1 and 2

Explanation:

µp/p0.e
p0.e.µp

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