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Question: Which of the following stands true for Effective memory access time for a process in demand paging? Where <strong><em>pr<sub>1</sub></em></strong><sub>  </sub>= probability that a page exists in memory, <strong><em>t<sub>mem</sub></em></strong> = memory access time , <strong><em>t<sub>pfh</sub></em></strong> = time overhead of page fault handling

Answer:

The effective memory access time can be improved by reducing the number of page faults. One way to achieving it is to load pages before they are needed by a process

MCQ: Which of the following stands true for Effective memory access time for a process in demand paging? Where <strong><em>pr<sub>1</sub></em></strong><sub>  </sub>= probability that a page exists in memory, <strong><em>t<sub>mem</sub></em></strong> = memory access time , <strong><em>t<sub>pfh</sub></em></strong> = time overhead of page fault handling

Correct Answer: A. Effective memory access time = pr<sub>1</sub> × 2 × t<sub>mem</sub> + (1 - pr<sub>1</sub> ) × (t<sub>mem</sub> + t<sub>pfh</sub> + 2 × t<sub>mem</sub>)

Explanation:

The effective memory access time can be improved by reducing the number of page faults. One way to achieving it is to load pages before they are needed by a process

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