1-d arrays using functions
Passing individual array elements to a function
We can pass individual array elements as arguments to a function like other simple variables.
Example:
#include <stdio.h>
void check(int);
void main()
{
int a[10],i;
clrscr();
printf(“\n enter the array elements:”);
for(i=0;i<10;i++)
{
scanf(“%d”,&a[i]);
check(a[i]);
}
void check(int num)
{
if(num%2==0)
printf(“%d is even\n”,num);
else
printf(“%d is odd\n”,num);
}
Output:
enter the array elements:
1 2 3 4 5 6 7 8 9 10
1 is odd
2 is even
3 is odd
4 is even
5 is odd
6 is even
7 is odd
8 is even
9 is odd
10 is even
Example:
C program to pass a single element of an array to function
#include <stdio.h>
void display(int a)
{
printf("%d",a);
}
int main()
{
int c[]={2,3,4};
display(c[2]); //Passing array element c[2] only.
return 0;
}
Output
2 3 4
Passing whole 1-D array to a function
We can pass whole array as an actual argument to a function the corresponding formal arguments should be declared as an array variable of the same type.
Example:
#include <stdio.h>
main()
{
int i, a[6]={1,2,3,4,5,6};
func(a);
printf(“contents of array:”);
for(i=0;i<6;i++)
printf(“%d”,a[i]);
printf(”\n”);
}
func(int val[])
{
int sum=0,i;
for(i=0;i<6;i++)
{
val[i]=val[i]*val[i];
sum+=val[i];
}
printf(“the sum of squares:%d”, sum);
}
Output
contents of array: 1 2 3 4 5 6
the sum of squares: 91
