This Portion of Electrical and Electronic Instrumentation contains Signal Conditioning MCQs (Multiple Choice Questions and Answers) / Objective Type Questions and Answers.

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• 6 pins
• 7 pins
• 8 pins
• 9 pins

• 0 V
• 400 V
• ±400 V.

#### 3. In order to eliminate the output voltage on account of input offset voltage,

• A nulling potentiometer is connected between pins 1 and 5 and potentiometer is adjusted to give zero output voltage. No voltage input is applied
• A nulling potentiometer is connected between ping 1 and 5 and sliding contact of the POT is connected to pin 4(V – of supply). The POT is adjusted to give zero, no input voltage is applied
• A blocking capacitor is used at the input of non inverting end
• An external offsetting potentiometer is used whose sliding contact is connected to the output terminal. This potentiometer is adjusted to give zero output voltage with no input voltage applied.

#### 4. An active half wave voltage follower circuit has an input of 10 sinωt V. The input resistance has value 2 kΩ and feedback resistance is 10 kΩ. The expression for input voltage is :

• 50 sinωt V for 0 < ωt < π, 0 V for π < ωt < 2π
• 60 sinωt V for 0 < ωt < π, 0 V for π < ωt < 2π
• 60 sinωt V for 0 < ωt < 2π
• 50 sinωt V for 0 < ωt < 2π

• 398 Hz
• 1592 kHz
• 125 × 103 Hz
• 398 kHz

• 10
• 4.29
• 0.6
• 15

• 1
• 0.1
• 0.01
• 0.001

#### 8. A differential amplifier has a common mode gain of 0.02. it has + 200 mV signals applied to each of its inputs. The amplitude of output signal is :

• 0 V
• 8 mV
• 4 mV
• None of the above.

#### 9. The output from a transducer has a frequency of 50 Hz. It modulates (amplitude modulation) a carrier having a frequency of 1 kHz. The output wave shape contains frequencies which are:

• 1000 Hz, 1050 Hz
• 1000 Hz, 950 Hz.
• 950 Hz and 1050 Hz.
• 2000 Hz ± 100 Hz

#### 10. The output from a transducer is a non sinusoidal wave having frequencies ω1, ω2, ω3, ω4. The carrier frequency is ωc. the frequency spectrum of output wave contains frequencies

• ωc ± ω1
• ωc ± ω2
• ωc ± ω1c ± ω2c ± ω3
• ωc ± ω1c ± ω2c ± ω3c ± ω4

#### 11. A low pass filter has a time constant of τ . its gain at a frequency ω is,

• √(1+ (ωτ)2 )
• ωτ/√(1+ ω2 τ2 )
• ωτ/√(1+ (ωτ)2)
• None of the above.

#### 12. A high pass filter has a time constant of τ, its gain at a frequency ω is,

• √(1+ (ωτ)2 )
• ωτ/√(1+ ω2 τ2 )
• ωτ/√(1+ (ωτ)2)
• None of the above.

#### 13. A input circuit of variable resistance transducer consists of a ballast resistance, in series with the transducer resistance Rt . The resistance of the transducer for a particular input is kRi, where k is a constant. If the input circuit is supplied by an input voltage ei. The sensitivity of the transducer is

• (ei Rb)/((Rb+ kRt))
• (ei Rb)/((Rb+ kRt))2
• (ei Rb)/((Rb+ kRt))3
• (ei RbkTt)/((Rb+ kRt))3

#### 14. In a voltage sensitive Wheatstone, having each arm having a resistance R, the resistance of one of the arm is changed to R+∆R where ∆R≪R. the Wheatstone bridge is supplied with an input voltage of ei, the output voltage on account of unbalance is

• ((∆R/R)/(2+∆R/R)) ei
• ((∆R/R)/(4+∆R/R)) ei
• ((2∆R/R)/(4+∆R/R)) ei
• ((∆R/R)/(4+2∆R/R)) ei

#### 15. The bridge sensitivity factor for a Blumlein bridge using two inductive transducers in push pull arrangement is,

• (2 Lc/ L)/((1+ Lc/ L))
• (4 Lc/ L)/((1+ 2Lc/ L))
• (4 Lc/ L)/((1+ Lc/ L))
• (2 Lc/ L)/((1+ 2Lc/ L))

#### 16. In a Blumlein bridge using two capacitive transducers in push pull configuration, the bridge sensitivity factor above the resonance frequency for a tightly coupled bridge is ,

• 2 and is independent of the variations of the bridge frequency and ratio arm inductance
• 2 and is dependent of the variations of the bridge frequency and ratio arm inductance
• Practically constant and is lower than that of bridge with uncoupled arms
• Variable and is dependent upon the frequency even though the ratio arms are tightly coupled.

• ωτ = 1
• ωτ << 1
• ωτ >> 1
• ωτ = 0

• ωτ = 1
• ωτ << 1
• ωτ >> 1
• ωτ = 0

#### 19. An 8 bit converter is used for a d.c range of 0-10V. find the weight of LSB.

• 39 mV
• 78 mV
• 39.2 mV
• None of the above.

#### 20. A 5 bit D/A converter has a current output. The digital input is 10100 and the output current corresponding to this is 10 mA. What will be output current for digital input of 11101?

• 10.5 mA
• 14.5 mA
• 29 mA
• None of the above.

#### 21. A successive approximation A/D converter has a resolution 20 mV. What will be its digital output for an analog input of 2.17 V ?

• 01101100
• 01101 101
• 01101011
• None of the above.

#### 22. A analog transducer has a range 0-10V. calculate its of an converter if the resolution is 5 mA

• 10
• 9
• 11
• None of the above

• 176 µV
• 705 µV
• 352 µV
• 1410 µV

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